Encryptor

That is true, however we are continuously accelerating towards its centre therefore a force is constantly applied on us by its gravity. But yes I do agree I shouldn't have factored in the sun now that I look at it since if the force is constant when we jump onto a weighing scale it will still have the sun's force included before or after a solar eclipse.

I got curious and wondered how much weight we lose while a solar eclipse is in effect so I calculated it here are my calculations please correct me if I'm wrong/made mistakes; Earth's g=9.81N/Kg Moon's gravitational pull acting on a man standing at the surface of the earth = ((6.67x^-11)x(7.35x10^22))/(384.4x10^6)^2 where 6.67x10^-11 is the gravitational constant, 7.35x10^22 is the mass of the moon, 384.4x10^6 is the distance from the moon to earth therefore moon's g on us is 3.318x10^-5 N/Kg. Now the sun; ((6.67x10^-11)x(1.989x10^30))/(149.6x10^9)^2 therefore sun's g on us = 5.928x10^-3N/Kg. so 9.81/9.81+(3.318x10^-5)+(5.928x10^-3) = 0.999393 so x100 = 99.94% of g therefore you are 0.06% lighter during a solar eclipse good time to measure your weight if you are on a diet