frederick

Ah, I used to be able to do this easily but I really have forgot by now...

Say you have a sphere with radius 10, you are drilling out a hole along the diameter with a radius of 3 inches... Find the volume of what's left of the sphere...

So the way I thought to do it was just y = sqrt(100-x^2) in range y>3 rotated around x axis, but I really did forget how to write this...

It was something like [math]pi \int^{10}_{3}(100-x^2)[/math]?

Merged post follows:

Actually, sorry for wasting your time, that seems to be about right.