Jump to content

antiphon

Members
  • Posts

    2
  • Joined

  • Last visited

Posts posted by antiphon

  1. Looks like there are multiple ways to understand this... let me present the usual way (at least for me) of solving elementary examples of conditional probabilities:

     

    Let [math]S[/math] denote the event that father scores, and let [math]R[/math] denote the event that the son reports scoring. The given probabilities are [math]P(S)=0.6[/math] and [math]P(R | S)=0.8[/math], and from the formulation of the problem it follows that [math]P( \bar R | \bar S)=0.8[/math] and [math]P(R | \bar S)=0.2[/math] (where [math]\bar A[/math] denotes the complement of [math]A[/math]).

     

    Now we can use Bayes formula + law of total probability to compute what we want:

     

    [math]P(S | R)=\frac{P(S \cap R)}{P®}=[/math]

     

    [math]=\frac{P(R|S) P(S)}{P(R|S)P(S)+P(R|\bar S)P(\bar S)}=\frac{0.8\cdot0.6}{0.8\cdot0.6+0.2\cdot 0.4}\approx 0.857 [/math].

     

    Notice that the probability goes up from 0.6 because we add information: this is the main idea of Bayesian thinking. A priori (before information from the son) we have more uncertainty about scoring, and afterwards, a posteriori, we are more certain.

     

    Cheers,

     

    Tuomas

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.