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Posts posted by frumpydolphin
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Geez I suck at this, a, b, and c act as the origin of the vectors, the direction is the direction of the vector from a, b, or c towards q
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Same time
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Ya, so there is a point(q) starting with coordinates xq and yq. Three other points a, b, and c have there x and y coordinates labelled in the same manner. A, b, and c exert a "push" on q each second suppose, and move it to the endpoint of a vector 2 times the magnitude of vector a,b, or c to q. The direction remains the same and the origin of the vector is still a,b or c. The average of the endpoints created by these vectors, 1 for a, 1 for b, and1 for c, gives q's position after 1 second. After n times though q's position would be the average of all these averages.
I derived the sum to n from 1 of the small averages divided by the number of seconds, so n, to get the final x and y values of q. (really need to figure out how to use equations)
Hope that helps but that is only the first part.
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Background
- System of points a, b, c and q
- a, b, and c exert a push on q moving it to the end of a vector that is 2 times the vector from a, b, or c to q.
- a, b, and c do this at the same time, after each cycle the x and y values of q are the average of the end points of the vectors.
- This happens n times
First derivation
The final x value is the sum of the averages of all the vectors endpoints divided by the number of iterations so n.
Same goes for y
I further thought why keep it at intervals when it can be a constant force.
From this I derived
The integral from 1 to n of the average of the averages of the vector endpoints in respect to the x value of q.
Same for y
Hope I wasn't too vague with it but am I at least close to right?
Also how do I insert equations?
This wasn't homework by the way don't rage at me.
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Movement of a point over time question
in Analysis and Calculus
Posted
Well, I can't think of a good way to explain so sorry for time waste. Thanks for trying to help though.