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Posts posted by Niha afzal
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Beautiful simply beautiful sensei the effort is much appreciated I can finally see what's happening here :') which made this thing much more simple:)
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But I think I dnt understand the question properly. .. if the fleas walk in a straight line and its a square cube how do they meet at the center thy must just walk 1 inch... how will they meeet ( this is getting confusing:( )
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In case 1 the electron moves In a straight line
In case two the field lines are shorter at the bottom than at the top
Force on electron is towards right the field lines also go from positive to negative I.e towards right .... but the electron is negative hence repels .. (therefore not sure about the path of electron.... it will depend on the fact which is stronger the p.d or the repulsive force by electron) maybe .
Foxy john if I were the elctron I would have chose to go.from the bottom ... lesser distance less time
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I have a theory question this time ... case 1
if I have two plates and theres a potential difference (p.d) across them 250 v ... an electron is fired from one end to the other end with some speed v m/s
Case 2
Now I take the same plates same p.d however the plates are not uniform this time..... willl this have any effect on the speed of the electron? Compared to case 1 ... or will the time change?
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Yessssss! !! :D
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Hmn so the potential energy at thestart of motion convert to kinetic energy (ke ) the ke is max at the bottom when ball is about to hit the groud so the potential energy at the begning converted to k.e
Now since the balll after rebound didnt go back to 80 cm some energy must have been lost as heat light ..
But in the upwards motion to the k.e getconverted potential energy.
Thats all I know about k.e and g.e
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Okay okay ojaay maybe we take the height as 80 -8 cm.... bcz we start the height frm center of gravity of baallll and end it at COG which makes a complete diameter
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Diameter 8 cm .. 0.08 m
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Oh so il take the height as .8-0.04 meters ....
Then the p.e will be mass× -9.81 × .8-0.04 ?
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Yes .... the squares get cancelled out leaving me with B
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Wwavelength of red is longer than blue .. I seee where I was making mistake. ... the freq of u.v is greater than infra.... which crosses D and the ans much be A
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B is wrong bcz longitudinal waves cant be polarised because they travel in only one plane .....
C is wrong bcz the relationship isnt correct the amp squared is directly proportional to the intensity not the energy....
B and c are both wrong...
But A AND D are both correct :/
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Intensity is the brightness of the wave ... and the eq INTENSITY DIRECTLY PROPORTIONAL TO AMPLITUDE^2 relates them
And amplitude is the maximum displacement of the wave
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Max k.e when the particle reaches the straight lineee.horizontal axis ...
Therefore in time T it comes to the straight line twice.... .. if negative max is zero velocity and the straight line is max velocity. ... in time T the particle makes 2 curves .. hence the option is D? Is it
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My approach for this question is..
The disp time graph will give us the speed .. the speed will give us kinetic energy 0.5mv^2 .
Now the disp time starts with a negative displacement. ..the particle at that point will have a gradient (speed) negative . .. but in the k.e eq the sped gets squared .. therefore the first kinetic energy must be positive having some value.... crossing part B AND D which start from zero.... now how do I chose from A AND C.... if my thoughtprocess is correct ...
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I did basic calculus .... im still doing my alevels ...therefore I have both physics and maths .. but basic math
This kinematics working was amazing.. who knew we could relate kinematics and elctricity like this.... this was amazing seriously yet im scared how will I figure out stuff like this. My best bet is practising a loooot! I find no words to thank you :')
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Electric fields
in Homework Help
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