san001

I took acid as HxA where A is anion. And the equation became

HxA + Mg -> MgxA2 + H2.

Then we know eq. wt. of H, Mg also we know the wt. of salt and acid.

I used concept that no. of gram eq. weights are equal. Also eq wt of acid = eq wt of H(1.008) + eq wt of anion (this is unknown say 'e') and eq wt of salt = eq wt of Mg(12) + ew wt of anion. And by solving

wt of acid/eq wt of acid = wt of salt/eq wt of salt.

I got e=35.38. Thus eq wt of acid=e+1.008=36.39.

Is this correct or not? But the ans given is 36.5.

i know about the term equivalent weight. Equivalent weight of magnessium is 12 and valency is 2. I have solved similar question in which known salt was given or equivalent weight of salt is given. I used "number of gram equivalent weight of acid = no. of gram eq. wt. of salt/or any other compound". Generaly number of gram equivalent weights are equal in a balanced equation. But in this question neither known salt nor eq. wt. of salt is given. Instead of this magnesium is added in the question. And i dont know how to use magnesium (or eq. wt. of magnesium) to find solution. Please give some hints.

I am sorry that I posted in wrong place. I am new and this is my first question. I am preparing for entrance exam and I am unable to solve this type of objective question. How to solve this question? I have posted full question here no any circumstances are given in the question.

should i post same question in homework section?

What is the equivalent weight of acid if 1.321gm acid reacts with magnesium to give 1.72gm salt?