xylia

having some trouble with this.

carbon disulfide is a covalent molecule that has a melting temperature of -110.8 C°. at room temperature 25C° and pressure 1 atmosphere carbon disulfide is a liquid. under the same conditions aluminium sulphide, an ionic compound , is a solid with a melting temperature of 1110 C° write the chemical formulas of these two substances:

so what i did is this:
Cs2+ Al2S3

but there is no chemical formula right? or I'm ai wrong?

(y-c)/m=x

yes right but isn't that what i did?

right because y=mx

I'm having some difficulty solving this problem,

we have x on the graph and its unknown , the gradient is of a straight line is 2.3 x10^4 the interception on the y axis is 5.8 x10^4 m we know y is 6.2x10^5 m

i need to find x

so i tried rearranging the equation

y=mx+c to get x=y/m-c but i get a rely high number so I'm guessing its not correct

please help me

thank you so much for your help, just one last question if we start from a speed of 0 m s can't i just write my formula anyway?

i do not know this equation, the only equation in my text book for speed is the one i wrote above

adding 3.0 m+ 0.6m giving the full distance till the water surface

point A must be 0 m s

v= squared( 2 g delta h)

i have drawn a diagram, but there are too many formulas and i can't rely find the right one because I'm rely comfused

I'm trying to understand, but i rely can't get it. i should calculate the velocity first against gravity with the jump then calculate the velocity by gravity with the initial speed of the jump? am i on the right path?

v= square root ( 2 g delta h)

or kinetic energy

or work done by gravity

work done against gravity

i have a school problem to do, but have no idea where to start of how!

a person of mass m wants to dive from a 3.0 m board above the water, by jumping off the board rises to a further 0.6 m, at what speed does m enter the water?

knowing that g is 9.8 m s^-1 ( acceleration due to gravity)