rasen58

Thanks v2 = 2ax x = L So then 1/2 of that final v = 1/2 sqrt(2aL) And the equation for distance is now just x = 1/2 at2 So we need to find a or t So a = (v-v0)/t and I then simplified that into t2=1/2 L/a And plugged that back into the distance equation to get 1/4 L. I think that's right?

A block of mass M starting from rest slides down a frictionless inclined plane of length L. When the block has attained 1/2 its final speed, the distance it has traveled along the plane is choices: L/4, L/2, L/sqrt(2), 3L/4 I tried using the equation V2=v02+2ax and set v0 = 1/2v which becomes 1/4 v2 to get 3/4 v2 = 2ax and then 3a/8 v2 = x But I don't think I'm doing it right. What should I be doing?