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Posts posted by ComplexCalcBro
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Hi, I am working on an assignment for my CSC class and I am having trouble with the code. I have an idea on what I would like to do. The purpose of the assignment is to make a simple game of craps. First time you roll if you land on a 7 or 11, you win automatically. If you roll on 2, 3, or 12, automatic loss. Anything else keep rolling until you and on a 7, then you automatically lose. If you can look at my code and let me know what you think of it, I truly appreciate it.
// JavaScript source code
// First going to create the bet functionfunction BtnBet_onclick() {//create variablesvar die1;var die2;var rolls = 1;var bet = document.getElementById("txtBet").value;var results = "";var NetMoney;var MoneyWonvar MoneyLoss;alert("1");// Roll 'em, Boys!die1 = (Math.floor(Math.random() * 6) + 1);die2 = (Math.floor(Math.random() * 6) + 1);var sum = die1 + die2;sum = die1 + die2;results += die1 + " + " + die2 + "==>" + sum + "\n";document.getElementById("txaResults").value = results;switch (results) { //This is for the first rollcase 7:case 11:alert("Winner!")MoneyWon += bet;NetMoney += MoneyWon;document.getElementById("txtmw").value = MoneyWon;document.getElementById("txtnm").value = NetMoney;break;case 2:case 3:case 12:alert("Sorry, try again!");MoneyLoss += bet;NetMoney = NetMoney - MoneyLoss;document.getElementById("txtml").value = MoneyLoss;document.getElementById("txtnm").value = NetMoney;break;case 4: //This is where I am thinking about making another loop.case 5:case 6:case 8:Case 9:case 10:alert("yo");break;}}0
Logarithms
in Homework Help
Posted · Edited by ComplexCalcBro
log5(x-1) + log5(x-2) - log5(x+6) = 0
[(x-1)(x-2)]/(x+6) = 0
(x-1)(x-2) = 0
therefore: x = 1; 2
Since the denominator can never be zero.