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adjarklo2000

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  1. let length be L, velocity be U , acceleration be A and time be T Li=1m, Lf=? Ui=1m/s, Uf=? A=? Uf=Ui+AT Uf=Ui, T=0 A=Uf/1= 1m/Square sec Lf=1/1=1m Lt= Li+Lf Lt=2m t=2/0.00001 t=200000s conclusion: the bug will reach the end in 200000 seconds by crawling a distance of 2 meters.
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