chey

If the Hubble constant were to be 2.0 x10-18 s-1, what would the age of the universe be, in seconds x1017? (1. ) (Find the number by taking the inverse of the Hubble constant. That means divide 1 by the Hubble constant. Just write the whole number that you get as a result in the following blank, with no decimal points or zeros.) What would that age of the universe be in billions of years? (2. ) (Find the number by dividing your previous answer by the number of seconds in a year. Round the resulting billions of years off to the tenths; for example if you calculated 19,779,300,000 years, which is 19.7793 billion years, you would just write 19.8). If the Hubble constant were to be 2.5 x10-18 s-1, what would the age of the universe be, in seconds x1017? (3. ) (Just give the whole number, no decimal points or zeros.) What would that age of the universe be in billions of years? (4. ) (Round the billions of years off to the tenths.) The current actually known value of the Hubble constant, to the tenths, is 2.3 x10-18 s-1. From that value, what is the age of the universe be, in seconds x1017? (5. ) (Write out the number including the five digits after the decimal point.) And finally, given that actually known value of H0, what is the age of the universe, in billions of years? (6. ) (Round the billions of years off to the tenths.)