The_goosse

... yes read it now. Carbon monoxide is the fuel is this what you mean? I am confused now its been a long day. I will pick this up in the morning. I have two weeks off work to study. Looks like I am going to need it. Cheers.

... O2 I hope this is leading somewhere... lol

... the carbon? The carbon is oxidized.

I don't know what burns right now studiot. This question burns actually. Unless you are referring to the fractions? I fully intend to use the x100 rule as soon as I have figured this one out. I will start again using the x100 rule and compare answers giving myself confidence that it works out the same either way. Not that I doubt you of course I just like to make sure I can do it another way before I change the way I already know. PS did you see my question in post #10?

... thanks guys. I just can't see where the (x-0.01) comes from, for the example I have shown the (x-0.01) is given so where did it come from? I will figure it out eventually. Hi studiot, are there any occasions when it would be unacceptable to use the x100 rule to get rid of the fractions? Cheers. ... when I set each side = to each other I get the following for L and R hand side (Ignoring N as stated) 0.02 + 2(x) = 0.04 + 2(x) So where does this (x-0.01) come form? should it be; 0.02+2(x) = 0.04, therefor x=0.01 I dont know why I am so stuck on such a simple example relative to the rest of the material it doesn't get any simpler than this lol. I cant see the wood for looking at the trees. (as they say)

I'm struggling with understanding how to get (x-0.01) for the products of oxygen. If I were given; 0.02 CO + (x) o2 + 3.76 (x) N2 > 0.02 CO2 + (??) O2 + (??) N2 I have no issue balancing the carbon I just struggle with the oxygen I have complete brain freeze!! Apologies if I have already answered this I just don't see it. Thanks again.

On the left O2 it is; 2(x) + 0.02 and on the right O2 is; 0.04 + 2(x-0.01) which is 2(x) + 0.04 - 0.02 so the answer is yes. Not sure about the other question? Because of the combustion process?

yes.

Please refer to the attached file. Can any one please explain to me where the (x-0.01) for O2 comes from? I have been stuck here for a long time. Thanks.