Zugag

Thanks a lot guys, now I know the technique. Have a great day!

Thanks a lot for the reply, but it's not a homework question, I am just learning basics for my upcoming course. So did you mean that simplified it is V^2 = 0 + 2×(9.6)×(400)? So for an answer i got V^2= 7680 m/s, and i know that it's completely wrong, so i'm doing something wrong here.

Hello all! I am new to the forum, so sorry if I post this into a wrong place. So I have been wondering about what if you would drop a coin, for instance off a building that is 400 meters tall, what would be its velocity when it hits the ground given the acceleration of 9.6 m/s^2 due to gravity. I have seen an other topic about the same problem, but it didn't help me at all. Can somebody please help me? Thank you!