raden gurnanda

ok... i got it, maybe the reaction will undergo by presence of the catalyst e.g:

ok i agree it.... but, what the oxidant involve in this reaction? who oxidize the pollutant...? H2O2...in what form....?

thanks a lot for your explanation... so, reaction (i) is unspontaneous reaction and it required the conditions as you mentioned above.... mmmm, then..if i use H2O2 alone -without any catalyst within- in order to treat the wastewater (remove its organic pollutant ), which reaction would be occured? do you think that On (monoatomic oxygen) could be an oxidant for organic substances? since it had two free radical... how strong is it?

Hi, there... i need your kind help to solve this problem, its about reaction decomposition of hydrogen peroxide.. which is true? (i) H2O2(l) → H2O(l) + O(g) or (ii) 2H2O2(l) → 2H2O(l) + 2O2(g) the former reaction produce monoatomic oxygen, named On , and act as oxidizing agent. (could anyone tell how strength is it?) while, the latter reaction is common reaction.. what the eligibility for both reaction..? thanks a lot for your prompt attention to this matter.. sincerely, Nanda -Dept.Physical Chem. Padjadjaran University, Indonesia-