C2H5OH Posted December 11, 2015 Share Posted December 11, 2015 Hello everybody I have a problem with one exercise. Dimedon shall react with NaOH and an excess of Br2. What is the product of the reaction? I thought about deprotonating the Dimedon between the two Keto-groups and form the enolat. But does the Br2 is added then or does something else happens first? Thanks for your help Link to comment Share on other sites More sharing options...
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