matinjanin Posted February 26, 2015 Share Posted February 26, 2015 The pairwise map distances for four linked genes are as follows: A-B = 14 m.u., B-C = 30 m.u., C-D = 34 m.u., B-D = 4 m.u., A-D = 18 m.u., A-C = 16 m.u. What is the order of these four genes? Choose one of the alternatives below. A) ABCD B) ADBC C) CBDA D) BADC E) CADB F) BACD G) DABC H) DBAC I) BDCA J) DBCA K) None of the above Link to comment Share on other sites More sharing options...
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