Chemistry Compounds

[Sgt Froggy]

I have a Chemistry Summer Assignment. I am about to take Ap Chemistry next year even though I haven't been in a Chemistry class since 9th grade. I forgot most of how to do compounds. If anyone can help that would be nice. I need to learn everything there is about compounds including naming, finding if it is ionic, and if it is insoluble. I have this Appendix G from the Beran Lab Manual, I don't know hwo to use it.

 

Directions: Name the following compounds using the new system (ex: Fe3+ is “iron (III),” not “ferric”). If the compound is ionic, put a check under the

“I” column. For the ionic compounds, write an “x” if it is insoluble in water (by following “Appendix G” – if it is not discussed, then write “n/a”).

1. NH4NCS 31. (NH4)HSO4

2. Al2O3 32. P2O5

3. KBr 33. NO2

4. K2S 34. (NH4)2SO3· H2O

5. SnI2 35. CCl4

6. SnCl4 36. IF7

7. Cu2O 37. Cl2O

8. CuSO4 38. Br2O3

9. Ag2S 39. Ba(OH)2

10. CsI 40. Cr2(SO4)3

11. Al2S3 41. Au(ClO3)3

12. Ni(NO3)2 42. ZrS2

13. AlPO4 43. NaClO3

14. MnSO3 44. HI

15. Fe(ClO4)3 45. NiH

16. GaCl3 46. Li2Cr2O7

17. Cr2O3 47. CoCl2 · 6H2O

18. KNO2 48. Mg(NO2)2

19. Rb2CrO4 49. H3PO4

20. (NH4)2HPO4 50. V(ClO3)2

21. Cs2CO3 51. Cr(ClO4)3

22. ZnCr2O7 52. Ba(MnO4)2

23. Mg(HCO3)2 53. Al(C2H3O2)3

24. Ca(ClO3)2 54. H2S

25. Sr(MnO4)2 55. Mn3(PO4)2

26. ScI3 56. CdC2O4

27. Fe(C2H3O2)3 57. RbIO4

28. Ag2SO3 58. Ra(NO3)2

29. Hg2Cl2 59. Ba(OH)2

30. TiO2 60. CuSO4 · H2O

 

Edit: I know how to find ionic now.

Edited July 27, 2014 by Sgt Froggy

[tarimshahab]

For Naming

The new system you mentioned, is ONLY used for ionic substances, and replaces as you say the old ferric/ferrous system.
Note also, that eihter of these systems is only needed for atoms that can exist with more than on oxidation number so basically the transition metals.

I'll explain the new system by an example: Fe₂O₃ .
So start by naming the metal, in this case iron. Then you have to figure out the oxidation number of the iron in the compound. You know that oxygen is almost always has oxidation number of -2. (Except in peroxides, in which it is -1). Anyway, so O is -2, and there are 3 of them, which gives a imaginary charge of -2*3= -6 coming from the oxygen. Since the whole compound is neutral, the -6 must be neutralized by the iron. So -6 / 2 = +3. There fore the oxidation number on the iron is +3.

Once you have the oxidation number on the metal you put it as roman numerals in brackets, without a space: iron(III)

Now just put the non-metal part in: iron(III) oxide.

Similarily CuSO₄ is copper(II) sulfate, because the oxidation of copper is +2.

 

For hydrates such as, CuSO4 · 5H2O, you must also name the water part. Just do this by using the greek prefixes: mono, di, tri, tetra, penta, etc.
So CuSO4 · 5H2O is copper(II) sulfate pentahydrate.

 

Solubility in Water

There are rules for these you will just have to memorize. The rules do have some logic to them, but memorizing is just easier. Here is a site with the rules.

http://www.chem.sc.edu/faculty/morgan/resources/solubility/

Edited July 29, 2014 by tarimshahab