Missvici101

n is the # of moles. m is the mass of the measured samples M is the Molar mass of the comound.

Hello, I need to calculate the yield % of [(Ph)3PH]2[CoCl4] The actual yield is 2.715g My issue is with the theoretical yield, here is how I did it: I'm following this reaction that was given in the explanations of my homework; (C6H5)3P + HCl => (C6H5)3PH+ + Cl- Molar mass of (C6H5)3P: 262.29 g/mol Molar mass of (C6H5)3PH+: 263.30 g/mol Mass of Triphenylphosphine measured: 1.062 g n(triphenylphosphine)=m(triphenylphosphine)/M(triphenylphosphine) =1.062g/(262.29 g/mol)=4.049×10-3 mol Molar mass of [(Ph)3PH]2[CoCl4] : 727.33 g/mol Since there are 2 molecules of (Ph)3PH in the [(Ph)3PH]2[CoCl4], the n(triphenylphosphine) needs to be divided by 2. n([(Ph)3PH]2[CoCl4])=n(triphenylphosphine)/2=2.025×10-3 mol m[(Ph)3PH]2[CoCl4] =n[(Ph)3PH]2[CoCl4] ×M[(Ph)3PH]2[CoCl4] m[(Ph)3PH]2[CoCl4] =(2.025x10-3 mol)×(727.33 g⁄mol) m[(Ph)3PH]2[CoCl4] =1.479 g = Theoretical yield You see, my theoretical yield is smaller than my actual yield. If someone sees my mistake, please let me know. Thank you, MV101

Hello, in an inorganic chemistry lab, three reactions were completed: 1) To TiOSO4 add zinc metal. The result observed is the following: A black gas is emitted from zinc, the solution experiences color changes; pink to grey to black 2) To TiOSO4 add the cupferron reagent. The result observed is the following: A bright yellow precipitate appears 3) To TiOSO4 add a solution of pyrocatechol. The result observed is the following: The solution changed to an orange-yellow solution. No precipitate observed. The solution was clear before. I need to represent the reactions with chemical equations. Any ideas? I did my research and didn't find anything in regards to these reactions. Please answer me, Thank you, MV101

Hello, in an inorganic chemistry lab we did the following reaction: To VOSO4 add a pinch of potassium hydrogen tartrate, 1mL of the p-phenetidine reagent, 1mL of saturated KClO3 solution and the 2mL of H2O. The result we get is a mixture with three distinct layers: Top layer is a transparent Grey-purple liquid, Middle layer is a brown-black bubble oil layer, Bottom layer is a white precipitate with a flaky appearance. In my report, I need to represent this reaction with chemical equations. Any ideas? I've done my research, and I don't find any information in regards to this type of reaction. Thank you for answering, MV101