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DiFerrara

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  1. oh nice links thanks I understand better this story of dry, you open my eyes hahah I'll try it, thanks for the advice !
  2. thanks for the links, before start calcul first I think all work interaction is of the expansion type and only thermal energy change is significant. For the initial property, I know the volume and pressure. with this information I go to the "saturated water and steam table" the look the properties of this condition I find for 5 bar presasure : 151.85 C boiling point, 2.669 kg/m3 steam density, 2.3289 kJ/kg K specific heat, 2747.54 kJ/kg specific enthalpy of steam, 640.12 kJ/kg specific enthalpy of liquid water, 2107.42 kJ/kg latent heat of vaporization - the mass of steam in the system ? steam density x volume initiale <=> 2.669 kg/m3x 0.8 m3= 2.1352 kg for the mass of steam I'm here, the problem is I didn't understand what means "80% dry to a final state of 2 bar" thanks for the help
  3. Hi scienceforums ! it's my first time in this forum. I need your help for a problem in thermodynamics. I just started this field so my knowledge it's limit for now. My problem : Steam in a cylinder-piston arrangement expands from an initial condition of 5 bar, 80% dry to a final state of 2 bar, dry saturated steam. The initial volume of steam is 0.8 m3. The process of expansion can be represented by a straight line on the p-V diagram. the mass of steam in the system ? [kg] the work done by the system ? [kJ] the change in energy of the system ? [kJ] the heat absorbed by the system ? [kJ] Maybe it's a simple problem but really I tried, nothing to do... I'm waiting your help...
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