Gamma Girl

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    Chemistry
  1. Protons in the NMR

    The answer key says the red hydrogen sees 3 peaks. How is that?
  2. Protons in the NMR

    H H How many Peaks does the red Hydrogen observe? I I ClH2C--C--C--CH2Cl I I H H Answer: 3 peaks Dilemma: I thought 5 peaks since the environment is similar. How does symmetry play a role here?
  3. Protons in the NMR

    Hypervalent, I reread what you wrote in the daylight hours. The doublet is due to the other hydrogen attached and has nothing to do with the t-butyl group. Where can I see more examples like this? All we talk about is neighbors when analyzing these problems. I see the stereogenic center, and the protons in the CH2 are diastereotopic and have different environments, but had no idea that the doublet came from the other H. I am grateful. Can you explain structure 3?
  4. Protons in the NMR

    addendum: doublet from structure 1 is from t-butyl No, the H's would not couple. n is 1 due to the t-butyl because the distance is 2 bonds. Explain structure 3 to me, please.
  5. Protons in the NMR

    Diastereotopic hydrogens form stereoisomers that are not mirror images when the H is replaced by another atom like Cl. Concerning structure 1, a study group influenced me to change the answer from 2 to 1 peak because there are no neighbors and also hence structure 3. I felt they had a point, but it has something to do with diastereotopic hydrogens according to you. There is a blurb on that in this chapter, but the teacher skipped that term this time.
  6. Protons in the NMR

    Case reopened. Structure 1= n is 0 because no neighbors, n +1= 0+1=1 The circled hydrogen has 1 peak. Structure 2= (n+1)(m+1)= (2+1)(1+1)=6 The circled hydrogens observe 6 peaks. Structure 3=n is 2, has 2 hydrogens as neighbors. (n+1) =(2+1)= 3 The circled hydrogen sees 3 peaks. None of the above are a choice in the pdf. Do you know how to approach this question? It is literally keeping me up nights.
  7. Protons in the NMR

    Hypervalent_iodine, I see your point. My thinking for 1 is incorrect. What is the correct answer for structure 1?
  8. Protons in the NMR

    CASE IS CLOSED. PROBLEM SOLVED BY WATCHING YOU TUBE AND KNOWBEE. STRUCTURE 1 - 2 PEAKS USING (n+1) [(0 peaks +1) from the left, (0+1) from the right because Deuterium is invisible] STRUCTURE 2- 6 PEAKS USING (n+1)(m+1) STRUCTURE 3- 1 PEAK OBSERVED DUE TO THE PLANE OF SYMMETRY n= proton neighbors attached to adjacent carbons
  9. Protons in the NMR

    n-1
  10. Protons in the NMR

    PLEASE DO NOT TORTURE ME FURTHER. I know for structure II (n+1)(m+1) rule for 6 peaks. For structure I, D makes it invisible on the left. I know t-butyl makes 1 peak from previous experiences but why again the 9 H integration? So n+1= 2 (again why isn't 9+1=10) For structure III, the symmetry of the molecule is inflicting a pain. I can tell you easily it has 2 NMR signal, but the splitting is a demon of another sort.
  11. Protons in the NMR

    Please open pdf. Organic question.pdf
  12. NMR and MRI

    No Elaborate, please. Actually, I understand now. Thank-you again.
  13. NMR and MRI

    The sample is a molecule. MRI deals with magnets like in CAT scans.
  14. NMR and MRI

    The different spin states creates different energy differences for NMR due to different frequencies.
  15. NMR vs MRI

    Why does a sample in an NMR spectrometer spin, but in an MRI the magnet spins?