chemgirl101

i think its unsaturated because dbe is 8 the 3 pie bonds =3 nitrile =2 ring =1 and c=o= 1 and c=c is 1 total of 8. i think the ch2 is bonded between the ester and ring. made a mistake typing ch3 i meant unsaturated .not saturated sometimes i mix them up. alkenes are unsaturated !

hi thanks! i believe the carbonyl is an ester and we didnt get spectrum with an alkene double bond. so a saturated ester. the dq has to be bonded to a ch3 and h . so where does this 2h singlet come in to play? is it between the ch3 and carbonyl

Compound A (C12H11NO2) IR : 2225, 1740, 1645, 1600 and 1505 cm-1 2.05δ (3H, dd, J = 7.10, 1.80 Hz) 3.65δ (2H, s) 6.10δ (1H, dq, J = 15.50, 1.80 Hz) 6.50δ(2H, d, J = 7.80 Hz) 7.40δ (2H, d, J = 7.80 Hz) 7.65δ (1H, dq, J = 15.50, 7.10 Hz also i have to get 2 isomers that will have the same ir spectrum . but ir cant distinguish isomers right? SO I PREDICTED MY MOLECULE TO HAVE A NITRILE GROUP AND 1 BENZENE RING and its 1,4 di substituted WHEN I DREW IT OUT I AM NOT GETTING A 2 H SINGLET . can you help me predict this molecule please. im guessing the 2 h singlet will be with a nh2 but the molecule has a double bond equivalence of 8. help is greatly appreciated

Hi im new to this group i have 2 questions to ask ,the troublesome one is based on benzene sulfonic acid does is react just like benzene sulfonation?