The evaluation or products --or fractions, for that matter-- does not depend on the base. Take, eg., \( 7\times3=21 \). In binary, the numbers \( 7 \) and \( 3 \) are written, \[7={\color{red}1}\times2^{2}+{\color{red}1}\times2^{1}+{\color{red}1}\times2^{0}={\color{red}1{\color{red}1{\color{red}1}}}\] \[3={\color{red}0}\times2^{2}+{\color{red}1}\times2^{1}+{\color{red}1}\times2^{0}={\color{red}0{\color{red}1{\color{red}1}}}\] You can even reproduce the algorithm for multiplic