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Primitive roots


caledonia
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Try induction on [math]x^2-1=0[/math] which has roots [math]\sqrt{1}[/math]. Clearly [math]-1[/math] is primitive since it is not a root for [math]x^1-1=0[/math]

 

i.e. assume for your induction hypothesis that the roots for [math]x^{n-1}-1=0[/math] are [math]^{n-1}\sqrt{1}[/math]

 

BUT beware of multiplicities!

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