Jump to content

Thermal energy and temperature


rasen58

Recommended Posts

There are two equal masses of silver insulated from each other. Sample A is maintained at 20 degrees C. Sample B has twice as much thermal energy as Sample A. Silver has a specific heat of 233 J/g*C. What is the temperature of sample B?
I don't have any idea how to do this and don't have that good of a grasp of the term 'thermal energy'.
I think thermal energy is equivalent to total kinetic energy of all the particles, so maybe you could use the formulas for average kinetic energy, but I'm not sure how.
q = cm dT
KEavg = (1/2)mv2 = (3/2)KT

 

Link to comment
Share on other sites

I am not sure what level you are working at or why you have been given the specific heat.

 

Here is a simple definition of Thermal Energy which leads to a simple equation, where the specific heats cancel in your case and results in an answer of

 

313oC

 

 

http://www.answers.com/Q/What_is_The_thermal_energy_of_a_solid

 

This definition ignores any expansion due to temperature rise. That is considers it insignificant.

To include this you need the coefficent of thermal expansion of silver.

 

If this is enough, post your working and we can discuss the difference between Thermal Energy, Internal Energy, Heat content, Heat capacity and their relationships to temperature, and the statement.

 

The temperatures of both samples of silver lie between what is known as the Debye temperature of silver (-43oC) and the melting point of silver (960oC)

We can discuss this as well if you like.

Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.