shafaifer Posted May 30, 2014 Share Posted May 30, 2014 Hello,I have these reactions (they should be correct):CaCO3(s) + HNO3(aq) --> H2O(l) + Ca2+(aq) + CO2(g) + NO3-(aq) Eq. 1 Calcium cations will now form a complex with water according the following reaction: Ca2+(aq) + 6H2O(l) --> [Ca(H2O)6]2+(aq) + 6H2O(l) Eq. 2 Now comes the combustion: This is a project of AAS (atomic absorption spectroscopy), and I want to measure the absorbance for calcium when irradiated with a hollow cathode lamp. I am only interested in calcium so I ignore water, nitrate ions and CO2(g). As a combustion agent / oxidising agent, C2H2(g)/O2(g) is used: [Ca(H2O)6]2+(aq) + C2H2(g)/O2(g) --> Eq. 3 What is the product of this equation? I am sure solid calcium is formed (thus reduced). But how can it be reduced when the compounds used for the combustion are oxidizing agents? I am considering C2H2(g)/O2(g). Link to comment Share on other sites More sharing options...
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