nindiya Posted November 9, 2013 Share Posted November 9, 2013 My teacher gave us an equation: nhcoohdeltaHhcooh+oh + nh30deltaHh30+oh = -(CcaldeltaTcal + cwaterVaciddeltaTacid + cwaterVbasedeltaTbase) & told us to find enthalpy of neutralization fo formic acid. given: hcooh + oh----h2o + hcoo h30+oh----2 h2o hcooh: t1=21.4, t2= 27.5, delta T=6.1 (* this was also the delta Tcal) naoh: 20.4, t2= 27.5 , delta T= 7.1 This is the information I calculated: 1. initial moles - nh30= 0.0632 (0.075mol - 0.011748mol) (which my teacher said to use the equation above with. We had to interpolate deltaHhcooh+oh ( which = -58517) However, I plugged in the values and got -57474.58. Please help. (* how to do the proper procedure) Link to comment Share on other sites More sharing options...
Amanbir Singh Grewal Posted November 9, 2013 Share Posted November 9, 2013 nindiya where is the T value for cal? Link to comment Share on other sites More sharing options...
nindiya Posted November 10, 2013 Author Share Posted November 10, 2013 my teacher said that the delta T value for cal = delta T acid (which was 6.1) I also calculated Ccal in a previous question and it was 30.269 which was the value I substituted in this equation above. I've attached my calc. *Note: the value of 0.063moles is the moles remaining of HCOOH Link to comment Share on other sites More sharing options...
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