ahmedmoon Posted June 1, 2013 Share Posted June 1, 2013 Hi Can please give me the idea for solving this quetion A Carnot engine operates between reservoirs at 20 and 200°C. If 10 kW of power is produced, the rejected heat rate is nearest Link to comment Share on other sites More sharing options...
studiot Posted June 1, 2013 Share Posted June 1, 2013 What have yo done so far? You already know the equations from your previous thread on this subject. Can you not rearrange them to to solve this one? Link to comment Share on other sites More sharing options...
ahmedmoon Posted June 1, 2013 Author Share Posted June 1, 2013 T teacher said the answer will be kj per second How is that .. I will try n = 1 - tmin / tmax So 1 - 293/473 = 0.38 THen power = work divide time What should I do next ?? Link to comment Share on other sites More sharing options...
EdEarl Posted June 1, 2013 Share Posted June 1, 2013 "If 10 kW of power is produced, the rejected heat rate is nearest" ... is an incomplete sentence. Nearest to what? Link to comment Share on other sites More sharing options...
daniton Posted June 1, 2013 Share Posted June 1, 2013 (edited) to the answer may be or approximately.... any way you find the efficiency and then the power delivered if it was 100% efficient in the end it's a matter of subtraction with the given power. Edited June 1, 2013 by daniton Link to comment Share on other sites More sharing options...
ahmedmoon Posted June 1, 2013 Author Share Posted June 1, 2013 A Carnot engine operates between reservoirs at 20 and 200°C. If 10 kW of power is produced, the rejected heat rate is nearest 26.3 kJ/s 20.2 kJ/s 16.3 kJ/s 12.0 kJ/s Above is full question please could help me Link to comment Share on other sites More sharing options...
swansont Posted June 1, 2013 Share Posted June 1, 2013 What is the relationship between total energy, useful work done and rejected heat? Link to comment Share on other sites More sharing options...
daniton Posted June 1, 2013 Share Posted June 1, 2013 A Carnot engine operates between reservoirs at 20 and 200°C. If 10 kW of power is produced, the rejected heat rate is nearest 26.3 kJ/s 20.2 kJ/s 16.3 kJ/s 12.0 kJ/s Above is full question please could help me This forum is actually to help anyone despite there scientific knowledge and in this thread (homework help) we help, but we don't do. In my previous post I try to show you how it is done. Just try it I'm sure you can get it. If you follow it you should get 16.3 Link to comment Share on other sites More sharing options...
ahmedmoon Posted June 1, 2013 Author Share Posted June 1, 2013 Total energy = work + change in heat . Please help me ... Link to comment Share on other sites More sharing options...
Fuzzwood Posted June 1, 2013 Share Posted June 1, 2013 Just look up the Carnot related formulas. You didn't put any effort in using them as far as I have seen. Link to comment Share on other sites More sharing options...
swansont Posted June 1, 2013 Share Posted June 1, 2013 Total energy = work + change in heat . Please help me ... And now the equation for efficiency in terms of these? Identify which variable you already know, because you have enough information to solve for the unknown. (which studiot has pointed out) Link to comment Share on other sites More sharing options...
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