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Compton Scattering Energy Equation?

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Could anybody point me in the right direction as to how one would derive the equation below?


[latex]E_{\gamma}'=\frac{E_{\gamma}}{1+\frac{E_{\gamma}}{m_0 c^2} \left(1- \cos \theta \right)}[/latex]


I read it in my lab manual along with the Compton Wavelength equation (which I know how to derive) and I'm wondering where it comes from.



Edited by x(x-y)
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Take your derivation of the compton scattering (which you say you are happy with) - at one point you will have


[latex]\lambda_{f} - \lambda_{i}= \frac{h}{m_{e}c}(1-\cos \theta)[/latex]


replace wavelength with hc/E ie planck relation


divide both sides by hc


subtract Ei from both sides


take reciprocals of each side


multiple top and bottom of RHS by Ei


clean up - and you have your equation. It's just a simple algebraic mix up of the standard equation and use of planck. Let me know if it doesnt work out when you try





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Yep that works - but you can skip a few of those last steps actually and get to the answer easily from


[latex]\frac{1}{E_2} - \frac{1}{E_1} = \frac{1}{m_e c^2} \left(1-\cos \theta \right)[/latex]


Anyway, thanks for the help.

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