Iota Posted February 16, 2013 Share Posted February 16, 2013 I've worked out a rate equation: rate=k'[A]a the nice and easy bit. Now I have to take the logs of both sides of the equation. The thing I'm confused about is that I have no values, it just wants me to show the equation with the logs of both sides taken, so would that literally be shown just as: ln rate= ln k'[A]a ? I'm not sure how to do that or if the answer would be as basic as writing log next to both sides? Link to comment Share on other sites More sharing options...
John Cuthber Posted February 16, 2013 Share Posted February 16, 2013 What do you know about ln(ab)? Link to comment Share on other sites More sharing options...
Iota Posted February 16, 2013 Author Share Posted February 16, 2013 Is it where: a to the power of x = b? Otherwise I'm afraid I do not. Link to comment Share on other sites More sharing options...
John Cuthber Posted February 16, 2013 Share Posted February 16, 2013 http://en.wikipedia.org/wiki/List_of_logarithmic_identities#Using_simpler_operations Link to comment Share on other sites More sharing options...
Iota Posted February 16, 2013 Author Share Posted February 16, 2013 (edited) Thanks, I need to improve my maths skills, a point in the right direction is always good. Right, would it simply be this: log rate= log k' + log [A]a I'm unsure what to do with [A]a, if anything at all. Edited February 16, 2013 by Iota Link to comment Share on other sites More sharing options...
John Cuthber Posted February 17, 2013 Share Posted February 17, 2013 It's slightly confusing that they use a twice If the expression was ....+ ln ([a]b) what would you do to it? Link to comment Share on other sites More sharing options...
Iota Posted February 17, 2013 Author Share Posted February 17, 2013 I was thinking it would possibly be this: log rate= log k' + b log([A]) Link to comment Share on other sites More sharing options...
John Cuthber Posted February 17, 2013 Share Posted February 17, 2013 You could look at the experimental data and plot the log of the rate versus the log of the concentration. Looks like a straight line to me, and physical chemists like straight lines on their graphs. From the slope of the line you can calculate a. 2 Link to comment Share on other sites More sharing options...
Iota Posted February 17, 2013 Author Share Posted February 17, 2013 I'll go do that, thanks for your help. Link to comment Share on other sites More sharing options...
mississippichem Posted February 17, 2013 Share Posted February 17, 2013 and physical chemists like straight lines on their graphs. From the slope of the line you can calculate a. Nothing more true has ever been posted here. Link to comment Share on other sites More sharing options...
John Cuthber Posted February 17, 2013 Share Posted February 17, 2013 Indeed, and they are quite fond of taking logs of things. I suspect that the chocolate log was invented by a slightly muddled physical chemistry professor. Link to comment Share on other sites More sharing options...
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