Chuquis Posted February 4, 2013 Share Posted February 4, 2013 first of all I would like to know how to simplify the following cos (-t)cos t - sin (-t)sin t? I have tried but i can't seem to get it. I get stuck. The other thing I am wondering about is why does cos(a-b) = cos (b-a) and sin(a-b) = sin(b-a)? I am not really sure how to put it in words but I think it is because they are both on the positive side of the x-axis but not both on the positive of the y-axis. I'm I on the right track or not? Link to comment Share on other sites More sharing options...
abvegto Posted February 4, 2013 Share Posted February 4, 2013 i guess the answer is 1....cos(-t) = cos t and sin(-t) = - sin t Link to comment Share on other sites More sharing options...
Crimson Sunbird Posted February 5, 2013 Share Posted February 5, 2013 The other thing I am wondering about is why does cos(a-b) = cos (b-a) and sin(a-b) = sin(b-a)? The second identity should be [latex]\sin(a-b)=-\sin(b-a)[/latex]. Let [latex]t=b-a[/latex]; then the two identities are as abvegto has pointed out: [latex]\cos(-t)=\cos t[/latex] and [latex]\sin(-t)=-\sin t[/latex]. Cosine is an even function and sine is an odd function. Link to comment Share on other sites More sharing options...
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