Jump to content

Inertia of Meter Stick


RVJ

Recommended Posts

So I'm currently working on some physics homework to prepare for an upcoming exam. We were assigned the following problem:

 

"Calculate the rotational inertia of a meter stick, with mass 0.56kg, about an axis perpendicular to the stick and located at the 20cm mark. (Treat the stick as a thin rod.)"

 

Here is how I attempted to solve the problem:

 

Using the Parallel-Axis Theorem,

I=Icom + Mh2

I found the Icom (using a table of values) to be:

(1/12)ML2

Filling it in for the equation:

I=(1/12)ML2 + Mh2

Knowing the values of every variable, I plugged in:

I=(1/12)(.56kg)(1)2 + (.56)(.3)2

 

My final answer was:

I=.097 kg-m2

But using the list of answers our Professor provided, it's supposed to be .97 kg-m2. I'm inclined to think the professor made a typo?

Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.