Jump to content

limit


daniton
 Share

Recommended Posts

i have two things in my mind

one the limit is 1 by using the property of limit in combination functions and since floor function is continuous at 1 that is the limit of sin(x)\x

the other is when using squeezing theorem we say that x is slightly greater than sin(x) so the ratio is less than 1so the floor of this is 0.

what do you say?????????????

Link to comment
Share on other sites

i have two things in my mind

one the limit is 1 by using the property of limit in combination functions and since floor function is continuous at 1 that is the limit of sin(x)\x

the other is when using squeezing theorem we say that x is slightly greater than sin(x) so the ratio is less than 1so the floor of this is 0.

what do you say?????????????

 

limit = 0 (your analysis is correct).

Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
 Share

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.