Samm Posted December 21, 2011 Share Posted December 21, 2011 Now I remember distinctly that one of my science teachers described to me a circuit that one could use to measure the potential difference of a galvanic cell; it's E0 value, ie. it's electric potential where there is no current. It involved a transformer, a micro-ammeter, the galvanic cell and a rheostat. I want to know how it works and possibly get more info on the subject. Cheers. Link to comment Share on other sites More sharing options...
John Cuthber Posted December 21, 2011 Share Posted December 21, 2011 (edited) This sort of thing? http://en.wikipedia.org/wiki/Potentiometer_(measuring_instrument) I can't see the point of a transformer- they only work with AC and a cell like that will never produce AC. Edited December 21, 2011 by John Cuthber Link to comment Share on other sites More sharing options...
TonyMcC Posted December 21, 2011 Share Posted December 21, 2011 (edited) Now I remember distinctly that one of my science teachers described to me a circuit that one could use to measure the potential difference of a galvanic cell; it's E0 value, ie. it's electric potential where there is no current. It involved a transformer, a micro-ammeter, the galvanic cell and a rheostat. I want to know how it works and possibly get more info on the subject. Cheers. I think you mean an adaptation of the circuit shown. The potentiometer would be replaced by two resistors, one fixed and the other a rheostat. I agree that there is no point in includind a transformer in a purely dc circuit. Edited December 21, 2011 by TonyMcC Link to comment Share on other sites More sharing options...
Samm Posted December 24, 2011 Author Share Posted December 24, 2011 (edited) About the transformer, I meant a power source which, while DC, could have its voltage changed. Sorry for the confusion. And yes, the pentiometer seems to fit exactly with what I remember about the circuit design. Edited December 24, 2011 by Samm Link to comment Share on other sites More sharing options...
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