Jump to content

max/min prob ?


1123581321
 Share

Recommended Posts

This seems a lot like a homework question. We generally don't provide complete answers to such things.

Perhaps you could make a start and we'll guide you through the rest.

Some questions to which the answers should get you started:

Do you know what the derivative of the cosine function is?

Do you know what the chain rule is?

Do you know what it means when the derivative of a function is zero

 

If you have more general questions (ie. you need an explanation of the chain rule) feel free to ask.

Edited by Schrödinger's hat
Link to comment
Share on other sites

I realise that you differentiate it first. but where do you go from there...?

Well, when the derivative is zero you have an extreme of your function. Can you solve your derivative for zero?

how exactly does u substitution leave you with 3x. and how do you differentiate pi ?

 

Hmm, pi is a constant, it doesn't change.

I'll give you another nudge along the way. We want:

[math]\frac{d}{dx}-3\cos{(4x-\pi)}=0[/math]

First, carry the constant out the front, it doesn't matter. We recognise we want to use the chain rule, so we can set [math]u=4x-\pi[/math]

and identify the rest as it as:

[math]-3 \frac{d}{du}\cos{u}\frac{du}{dx}=0[/math]

(If you need more explanation of how/why this works, do ask)

Splitting our problem into two problems we hopefully already know how to solve:

First, the derivative of [math]\cos{u}[/math] with respect to u (you can safely ignore what u might depend on, and all the rest of the problem for this step)

Second, the derivative of [math]4x-\pi[/math] with respect to x.

One thing that might help is to remember that derivatives are linear, the derivative of the sum is the sum of the derivatives.

Hopefully you can do: [math]\frac{d(4x)}{dx}[/math] easily enough.

And you asked what the derivative of [math]\pi[/math] (with respect to x) is.

Think about what 'derivative' means.

How fast does the value of [math]\pi[/math] change as we change x?

Edited by Schrödinger's hat
Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
 Share

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.