Heinsbergrelatz Posted August 7, 2011 Share Posted August 7, 2011 How do you solve equations like this?? -0.5lnx= x^2 the only way i cant think of is expanding lnx as a series and get an approximate answer, but that is as good as it gets. Can anyone help me please?? thank you Link to comment Share on other sites More sharing options...
Fuzzwood Posted August 7, 2011 Share Posted August 7, 2011 Is this an appropriate equation, or did you come up with it? Link to comment Share on other sites More sharing options...
Shadow Posted August 7, 2011 Share Posted August 7, 2011 I'm no expert in these matters, but I'm next to positive you'll be needing the Lambert W Function. Link to comment Share on other sites More sharing options...
khaled Posted August 7, 2011 Share Posted August 7, 2011 [math]- 1/2 ln(x) = x^2[/math] [math]ln(x) = - 2 x^2[/math] You need to use Lambert W Function, as Shadow said .. regarding your equation have complex roots, here is the solution from Wolfram|Alpha Link to comment Share on other sites More sharing options...
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