lemur Posted June 8, 2011 Share Posted June 8, 2011 The following post explaining my comparison of weight and voltage as expressions of potential energy has been contested as being "gibberish:" electric charge 'pushes' against an insulator with the amount of voltage it is poised to transmit at the moment the circuit closes. Thus I think it is reasonable to compare weight to voltage, where an obstacle preventing an object from falling impairs gravitational motion in the same way an insulator prevents an electric charge from flowing further within the circuit. In both cases, force is met with resistance and the "equal and opposite reaction" of the resistance is the potential of the impeded kinetic energy (flow). If this reasoning is incorrect, I of course want to hear why, but I see nothing faulty about it, honestly. What is gibberish? The idea that "electric charge 'pushes' against an insulator?" What else would it be doing while waiting for sufficient voltage to build up to the point of being able to spark across a gap in the circuit or some other insulator separating the conductors? Is it gibberish to say that "an obstacle preventing an object from falling impairs gravitational motion in the same way an insulator prevents an electric charge from flowing further within the circuit?" If a bowling ball dropped out of a helicopter is stopped by a bridge on the way to the ground, is the bridge not impeding the flow of the ball to the ground? Is it gibberish to say that "in both cases, force is met with resistance and the "equal and opposite reaction" of the resistance is the potential of the impeded kinetic energy (flow)?" Ok, this one is a bit harder to read but it applies a Newtonian principle, that actions have equal and opposite reactions. That means that a moving object resisted by a medium or barrier pushes against the barrier with force, which is returned in an equal and opposite force from the medium/barrier to the object. That force resisting the kinetic flow is the potential energy the flow has to continue in the absence of the resistance, no? Maybe I could have worded it differently, but this is all physics, is it not? Link to comment Share on other sites More sharing options...
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