MDJH Posted June 20, 2010 Share Posted June 20, 2010 I know I've asked about this before, but I was thinking of how to do water electrolysis in a reasonably efficient and/or relatively inexpensive manner. One idea I had was to set up a bucket, throw in some epsom salt (my current bag of epsom salt doesn't specify whether it's the heptahydrate or some other concentration of it though) and add tap water and stir until it's either all or mostly dissolved. Then I'd put in a couple plastic or glass bottles, (one about twice the size of the other) immerse them in the solution until they are filled, then find some way to fasten them upside-down (ie. the open end is facing downwards) and have electrodes set up so as to be insulated outside the bucket, on its way into the bucket, and just about everywhere except either inside the bottles or just below such bottles (preferably the latter, so long as the bubbles would go into the container, since I'd like both bottles to be filled with their respective gases) and connect said electrodes to a power supply that would consist of a combination of AA and AAA batteries connected primarily in parallel, through means of one piece of aluminum foil across all their positive terminals, and another piece of aluminum foil across all their negative terminals. This raises a few questions: 1. How long would it take epsom salt to either reach saturation or get fairly close to it? I ask this because with an unspecified concentration, I wouldn't know how concentrated the epsom salt would be until I brought it to near saturation through stirring, but I wouldn't want to assume too soon that the epsom salt was saturated. 2. A related question, how much voltage does it take to drive electrolysis with epsom salt as the electrolyte, and to what extent does it depend on the concentration? 3. And related to question 2, how would the current be drawn if the batteries are connected in parallel? Would it draw a variety of voltages (ie. from varied effectiveness of the batteries) or would they average out? Would the current be drawn as if each battery-water-battery loop were its own circuit, or as if the combination of batteries were an average power source and the water was the resistor? Link to comment Share on other sites More sharing options...
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