# Zero to the Zero

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Isn't it $0^0[/math'], which means "how many 0s are there in 0" = 1. That's 0/0, and in any case your reasoning is hideously flawed. One 0 makes 0. Two 0's (0*0 or 2*0) make 0. Three 0's (0*0*0 or 3*0) make 0. And so on to infinity. Which one of those is 'right'? ##### Link to comment ##### Share on other sites • Replies 58 • Created • Last Reply #### Top Posters In This Topic #### Popular Days #### Top Posters In This Topic #### Popular Days They most definitely are not. However' date=' 0^0 should be strictly speaking undefined, as the proof by notation that works for x^0 where x =! 0 doesn't hold if x = 0.[/quote'] why not? 0/0 is like 0^a/0^a=0^(a-a)=0^0 now why this is wrong? wait a minute perhaps it's not the same because zero can be represented in infinite state of powers: 0^a/0^2a=0^(a-2a) ##### Link to comment ##### Share on other sites • 1 month later... 0^0 is an "indeterminate", which is different than an undefined value. It means that it has been proven to be unexplainable. There are other indeterminates such as infinity^0, infinity/infinity, infinity/0, and some others. ##### Link to comment ##### Share on other sites Sorry, I am too lazy to have a look at this passage. I support what lgg say, 0^0=undefined=0/0, right? ##### Link to comment ##### Share on other sites hmm you're not right 1, In High School Math, 0^0 and 0/0 are both undefined. 2, But in University, I am not sure. 3, Even if 0^0 is undefined, you cannot say 0^0 'EQUALS' undefined. It's a serious mistake. ##### Link to comment ##### Share on other sites hmm you're not right 1' date=' In High School Math, 0^0 and 0/0 are both undefined. 2, But in University, I am not sure. 3, Even if 0^0 is undefined, you cannot say 0^0 [b']'EQUALS'[/b] undefined. It's a serious mistake. 1. True. 2. They still are undefined at the University level, and beyond. 3. True. ##### Link to comment ##### Share on other sites 0^0 is the same as 0/0, that's why x^0, where x is not 0 is x/x=1 ##### Link to comment ##### Share on other sites 0^0 is the same as 0/0, that's why x^0, where x is not 0 is x/x=1 What you're arguing from is the fact that that x^n/x^m generally equals x^(n-m), but it dods not neccessarily follow that x^0 = 0/0. You should be very, very careful about equating any intdeterminate or undwefined values. ##### Link to comment ##### Share on other sites its like dividing anything by zero, it must be undifined...but mathmatically it comes out to 1...but thats probably just off of a theorem...Im sure there's a proof behind it. ##### Link to comment ##### Share on other sites my TI83+ said it is undefined. it said "ERR:DOMAIN" ##### Link to comment ##### Share on other sites its like dividing anything by zero, it must be undifined...but mathmatically it comes out to 1...but thats probably just off of a theorem...Im sure there's a proof behind it. Say what now? ##### Link to comment ##### Share on other sites is there a proof behind dividing something by 0...or a proof for having 0 to the 0?? My palm calculator probably just made it =1 because it was raised to the 0th power, and anything to the 0th is 1...even tho its undefined ##### Link to comment ##### Share on other sites Dividing anything by zero is an undefined operation. It's not really linked to 00 as far as I know. ##### Link to comment ##### Share on other sites yea i know, but its the same outcome...thats all i was saying ##### Link to comment ##### Share on other sites Well, not really. Read post #5: generally 00 is regarded to be 1. ##### Link to comment ##### Share on other sites strange that so many calculators would come out with undefined...I have only tried it on one calc and found it to be 1 ##### Link to comment ##### Share on other sites Well, not really. Read post #5: generally 00[/sup'] is regarded to be 1. So far, my book told me x^0=1 when x is not equal to 0. ##### Link to comment ##### Share on other sites 0^0 is an "indeterminate", which is different than an undefined value. It means that it has been proven to be unexplainable. There are other indeterminates such as infinity^0, infinity/infinity, infinity/0, and some others 0^0 is just undefined. You end up with indeterminate quantities when while taking a limit both numerator and denominator approach 0. But then too there is the easy way out of applying L'Hospital's rule and getting a value. Indeterminate merely implies that it may have different values in different situations. ##### Link to comment ##### Share on other sites So far, my book told me x^0=1 when x is not equal to 0. Read the link in my first post on the subject. ##### Link to comment ##### Share on other sites 0^0 is not 1. 0/0 does not equal one, because 0 can be contained in 0 in more times than just 1. It's perhaps all real values, kinda like if x=a^2; then x has two solutions, a and -a, but that doesn't mean a=-a. In order for modern mathematicians to get this problem out of their way instead of solving like the good ol' times, they went ahead and said, "It's undefined." ##### Link to comment ##### Share on other sites 0^0 is not 1. Correct. 0/0 does not equal one, Correct. because 0 can be contained in 0 in more times than just 1. Nope. It's due to the fact that [math]a/b = c \iff a = b \cdot c$, where $c$ is unique for a given $a$ and $b$. Note that if $b=0$ and $a$ is fixed, c can be any value, and therefore, it is not unique. Thus, division of any number by $0$ is undefined.

It's perhaps all real values,
Nope. Division of two real numbers is not a multiple valued operation. An example of a multiple valued operation is $\pm$. An example is the quadratic formula (i.e. if $f(x)=ax^2+bx+c, x=\frac{-b\pm \sqrt {b^2-4ac}}{2a}$).

In order for modern mathematicians to get this problem out of their way instead of solving like the good ol' times, they went ahead and said, "It's undefined."
Assigning a numerical value to these concepts that does not conflict with the definitions of division is currently, and may never be, possible. Thus, the "undefined" moniker.
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0/0=R and all imaginary numbers.

if a/b=c, and a is 0, then c is 0 and can't be any other number but 0.

+or-, thanks for the reminder. For the sake of logical thought and processing, since there can be two values for a quadratic equation, and 3 for a cubic, and so on, for x/0, or rather 0/0 there are in infinite number of solutions.

0/0=? 1

0/0=1/1*0/0

0/0=0/0 correct

All real numbers and imaginary numbers follow the same pattern if 1 is replaced by x or any variable that you choose.

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0/0=R and all imaginary numbers.

if a/b=c' date=' and a is 0, then c is 0 and can't be any other number but 0.

+or-, thanks for the reminder. For the sake of logical thought and processing, since there can be two values for a quadratic equation, and 3 for a cubic, and so on, for x/0, or rather 0/0 there are in infinite number of solutions.

0/0=? 1

0/0=1/1*0/0

0/0=0/0 correct

All real numbers and imaginary numbers follow the same pattern if 1 is replaced by x or any variable that you choose.[/quote']

isn't 0/0 undefined?

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• 2 weeks later...

It's not only undefined, it's infinity.

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