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Median and variance


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If it is a binomial distribution then:

[math]\mu=np[/math]

[math]\sigma=(np(1-p))^{2}[/math]

so [math]\sigma=(\mu(1-p))^{2}[/math]

and in a normal distribution the medians is equal to the mean so you should be able to relate the two. Hope this helped.

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  • 2 months later...

In general if your distribution is symmetrical, then the median and mean are the same. Remember that the 3 sigma rule relates to normal distributions. If you do not have a normal distribution then the 99.7% does not apply. The percent might be higher or lower - it all depends on your data.

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