Jump to content
Sign in to follow this  
einsteinium

Could It Be Possible For V>3e8 m/s

Recommended Posts

Is it possible for an object with a constant acceleration to exceed the speed of light relative to its point of origin?

 

What force would be exerted upon the object if it were to lose acceleration when nearing c ?

 

The particle would be accelerating in the exact opposite direction if Einstein's theory does hold true. But why is the object deccelerating?

 

If it's true that their is no limit on acceleration then what makes a photon accelerate away from its source then accelerate in the opposite direction so that V is not greater than 3e8 m/s ?

 

An impulse of energy must be exerted on a photon to make it accelerate from its source within a givin time interval, according to Newton's first and third laws.

 

If photons reach C instantaneously then A is infinite as t = 0

eg, V = U + At

 

Where

V = final velocity (m/s)

U = initial velocity (m/s)

A = acceleration (m/s^2)

t = time (s)

 

3e8 = U + At

 

either U = 3e8 or time and Acceleration are greater than zero

 

If the initial velocity of a photon is zero then what is the time interval and acceleration for which photons reach C ?

 

It has been found that light does react with gravity, i.e a double vision of a galaxy behind another was found and the scientist believes that the light has been bent in the vacuum due to the gravitational field strength of the galaxy in front causing a double vision to occur.

Edited by einsteinium

Share this post


Link to post
Share on other sites

Photons don't accelerate, their velocity is always c.

Share this post


Link to post
Share on other sites

But what about when a photon reflects off a mirror? It would have to change its velocity vector to move in the opposite direction, like if you throw a bouncing ball toward a wall(v = x m/s), it would accelerate in the opposite direction in order to bounce off and away from the wall(v = -x m/s)

 

I see how they assume that photons have a constant velocity according to the equation, v = u + a.t , But when light refracts through a transparent materiel it does so because its velocity decreases which makes the light bend away from the normal. Now this would involve some form of acceleration or could it be related to the energy levels of the photons.

 

A physics experiment has brought light to an almost stand still using a form of gas which must also involve some form of acceleration in order for the photons to decrease in velocity.

 

Maybe the particle accelerator could help investigate some of the yet to be discovered properties of electromagnetic radiation.

Share this post


Link to post
Share on other sites
But what about when a photon reflects off a mirror? It would have to change its velocity vector to move in the opposite direction, like if you throw a bouncing ball toward a wall(v = x m/s), it would accelerate in the opposite direction in order to bounce off and away from the wall(v = -x m/s)

 

I see how they assume that photons have a constant velocity according to the equation, v = u + a.t , But when light refracts through a transparent materiel it does so because its velocity decreases which makes the light bend away from the normal. Now this would involve some form of acceleration or could it be related to the energy levels of the photons.

 

A physics experiment has brought light to an almost stand still using a form of gas which must also involve some form of acceleration in order for the photons to decrease in velocity.

 

Maybe the particle accelerator could help investigate some of the yet to be discovered properties of electromagnetic radiation.

 

It doesn't bounce; It is absorbed and re-emitted. Same with the "slowing down" of light. There is a delay between the absorption and the re-emission, so while the instantaneous velocity is always c, the average velocity can be a lot lower.

Share this post


Link to post
Share on other sites

 

It has been found that light does react with gravity, i.e a double vision of a galaxy behind another was found and the scientist believes that the light has been bent in the vacuum due to the gravitational field strength of the galaxy in front causing a double vision to occur.

 

The bending of light's path when passing a massive object is due to the curvature of space-time. The light follows a geodesic, which is the shortest path it can take. When seen from outside of the curved space-time region, the path appears curved.

 

You see the same thing when you look at maps of airline flight paths. Especially over long flights, jets fly along a geodesic which is the shortest route. If you plot these paths on a map, the lines looked curved:

 

http://www.aaronkoblin.com/work/flightpatterns/FlightMapColor1.jpg

 

So, for instance, if you want to travel to a point due West of your present position, in the Northern hemisphere you would fly a course that starts out at a little North of West, and then gently curves to just South of West on arrival. ( On a globe, geodesics follow "Great Circles" which are circles that bisect the globe. For instance, the Equator and all the lines of longitude follow great circles, the Northern and Southern lines of latitude do not.)

Share this post


Link to post
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
Sign in to follow this  

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.