hell_ever Posted December 28, 2008 Share Posted December 28, 2008 Say im reacting a base with a halobenzene with strong electron withdrawing groups at o- and p- positions. My textbook says this reaction will take place, albeit slowly, as the e- withdrawing groups will delocalize the charge on the intermediate carbanion. But my doubt is, won't the charge be on the carbon meta to these groups, so that the -M effect won't affect the charge at all? Link to comment Share on other sites More sharing options...
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!Register a new account
Already have an account? Sign in here.Sign In Now