crazziekid82 Posted June 5, 2008 Share Posted June 5, 2008 i am stuck on this question and for the life of me i cant figure out how they got the answer!? here are the details i have Preparation of a diluted soultion of household ammonia in which 20.00ml of household ammonia is diluted to 100.0ml dilution 5:1 Titrating the diulted ammonia with the standardised hydrochloric acid solution. in this step 20.00ml aliquots of dilute ammonia required 24.5l ml of hydrochloric acid for equivalence n(NH3) in 20 ml =1.177 x 10-2 mol The percentage of ammonia NH3(aq) is household ammonia. Take the density of the household ammonia to be 1.08g mL-1.. the answer is 4.46% However when you use the %= solute/ solution doesn't give the right answer.... am i missing something? Link to comment Share on other sites More sharing options...
hermanntrude Posted June 5, 2008 Share Posted June 5, 2008 what answer do you get, then? perhaps you didnt take into account the 5:1 dilution? Link to comment Share on other sites More sharing options...
crazziekid82 Posted June 5, 2008 Author Share Posted June 5, 2008 the final answer is 4.46% Link to comment Share on other sites More sharing options...
hermanntrude Posted June 9, 2008 Share Posted June 9, 2008 I meant what answer do you get when you do it your way (when you get a different answer to the correct one)? Link to comment Share on other sites More sharing options...
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