daniellao Posted May 8, 2008 Posted May 8, 2008 Naphthalene, a substance present in some mothballs, has an enthalpy of vaporization of 49.4kl/mol. If the vapor pressure of naphthalene is .300mmhg at 298K, what is the temp at which the vapor pressure is 7.6x10^2mmhg?
DeanK2 Posted June 19, 2008 Posted June 19, 2008 Revise phase equilibria and Raoults law. [math]P=P^ym[/math] P is the vapour pressure of the solution, [math]P^y[/math]=vapour pressure of the pure solvent [math]m[/math]=mole fraction of solvent in the solution. Use [math]pV=nRT[/math] to find kelvin.
hermanntrude Posted June 19, 2008 Posted June 19, 2008 what you need here is nor raoult's law or the ideal gas law, what you need is the clausius clapeyron equation. Look it up in your textbook.
ChemSiddiqui Posted June 25, 2008 Posted June 25, 2008 Ideal gas equation should help! I agree with DeanK2
hermanntrude Posted June 26, 2008 Posted June 26, 2008 (edited) honestly, the ideal gas law might or might not help, but the clausius clapeyron equation is designed for exactly this situation: [math]\ln(\frac{P_{2}}{P_{1}}) = \frac{\Delta H_{vap}}{R}(\frac{1}{T_{1}}-\frac{1}{T_{2}})[/math] apologies for the non-greek spelling for delta, but latex wouldnt accept the symbol. Note that you're given the deltaHvap and T1 and P1 and P2. just solve for T2 Edited June 26, 2008 by Cap'n Refsmmat fixed the greek - you just needed to put a space after it and a \ before it. - ecoli (also fixed the ln - Cap'n)
iNow Posted June 26, 2008 Posted June 26, 2008 For future reference, [math]\Delta[/math] is obtained by [math]\Delta[/math] Cheers. EDIT: Never mind. Looks like you figured it out all on your own.
ecoli Posted June 26, 2008 Posted June 26, 2008 EDIT: Never mind. Looks like you figured it out all on your own. that was actually my doing... "last edited by ecoli..."
Dave Posted June 26, 2008 Posted June 26, 2008 You use \ln. You can click on the latex image to display the code, just so you know.
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