ChemSiddiqui Posted February 14, 2008 Share Posted February 14, 2008 Alright I was doing some statistics questions and I have a probelm. Here goes: The random variable Z is distributed such that Z find the probalility: P(lZl < 1.3) NB. < is actually less than equal to. My solution: P( -1.3< Z < 1.3) P(z<1.3) - [ 1- P( Z < 1.3)) After putting values from the table 0.9032 - (1-0.9032). 0.9032 -0.9068 = -0.0036 (probalility can't be negative so my answer is wrong, mark scheme is saying the answer is 0.8064) Thanks in advance. Link to comment Share on other sites More sharing options...
DrP Posted February 14, 2008 Share Posted February 14, 2008 The random variable Z is distributed such that Z find the probalility: P(lZl < 1.3) NB. < is actually less than equal to. I think there should be more info. Link to comment Share on other sites More sharing options...
Bignose Posted February 14, 2008 Share Posted February 14, 2008 even with the missing info (which really is missing CS!), I think that 1-0.9032 is not 0.9068 Link to comment Share on other sites More sharing options...
ChemSiddiqui Posted February 15, 2008 Author Share Posted February 15, 2008 Bignose I figured it out later that I was doing alright. The solution was right but my substraction wrong (I had put my calculator in a diffrent mode). Thanks any way. Link to comment Share on other sites More sharing options...
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