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Fourier Series


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I know i can't change the title but i solved the problem i was looking for originally and need help with another...


The question says to use an integrating factor to solve:


x(dy/dx) = y + (y^2)x


The problem comes at the very last part to find v' and v because of the y^2 term.


The factor i'm using is: y = v*exp(-integral[-1/x]dx) where the -1/x is the term infront of the y when you divide by x and bring it across.


Any pointers would be great. Thanks.

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x(dy/dx) = y + (y^2)x

Do you mean [math]x\,\frac{{dy}}

{{dx}} = y + xy^2[/math]?


This is not a linear ODE, so you can't solve it with integratin' factor method. This is actually a Bernoulli's Differential Equation.

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