danny8522003 Posted December 29, 2007 Share Posted December 29, 2007 I know i can't change the title but i solved the problem i was looking for originally and need help with another... The question says to use an integrating factor to solve: x(dy/dx) = y + (y^2)x The problem comes at the very last part to find v' and v because of the y^2 term. The factor i'm using is: y = v*exp(-integral[-1/x]dx) where the -1/x is the term infront of the y when you divide by x and bring it across. Any pointers would be great. Thanks. Link to comment Share on other sites More sharing options...

thedarkshade Posted December 30, 2007 Share Posted December 30, 2007 I don't know the answer but a google search got me to this! Link to comment Share on other sites More sharing options...

K!! Posted January 3, 2008 Share Posted January 3, 2008 x(dy/dx) = y + (y^2)x Do you mean [math]x\,\frac{{dy}} {{dx}} = y + xy^2[/math]? This is not a linear ODE, so you can't solve it with integratin' factor method. This is actually a Bernoulli's Differential Equation. Link to comment Share on other sites More sharing options...

Math Team Posted February 2, 2008 Share Posted February 2, 2008 The hint to solution is the following: Substitute y from both sides of the equation, devide everything by x*y and look carefully on the left hand side of this equation. 1 Link to comment Share on other sites More sharing options...

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