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Potassium dichromate reaction


bio90

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Still a bit clueless on the products. I've managed to find out this though, when potassium dichromate is reduced, this is the half equation:

Cr2O72+ + 14H+ + 6e- --> 2Cr3+ + 7H2O

And I think the H+ comes from the acidified solution that the potassium dichromate is in.

 

And I think the formula for ammonium iron(II) sulphate is:

Fe(NH4)2(SO4)2

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Thanks, that's a great help, I have guessed then that the (unbalanced) reaction is:

K2Cr2O7 + Fe(NH4)2(SO4)2 + 7H2SO4 → K2SO4 + (NH4)2SO4 + Cr2(SO4)3 + Fe2(SO4)3 + 7H2O

 

But I have been fiddling around with it pretty much since your post and I can't balance it (feeble brain huh). I can manage to get the ammoniums andand everything else to balance, but never the sulphates. I couldn't seem to get enough of them on the left hand side, so I changed the H+ to H2SO4, but even so, I couldn't balance it..does it involve some pretty large numbers?

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