Nivvedan Posted September 1, 2007 Share Posted September 1, 2007 Can you give me the energy expression for an electron? And also, does the energy of an electron decrease, or does the energy of the Energy shell decrease while moving nearer to the nucleus? Link to comment Share on other sites More sharing options...
BenTheMan Posted September 1, 2007 Share Posted September 1, 2007 Nivvedan--- I'm not sure what you're asking for, but... [math]E^2 = m^2c^4 + p^2c^2[/math] Also, the ionization energy (that is, the energy that you have to expend in breaking the electron away from a neucleus) goes up like the atomic number (Z) squared, I think. Don't quote me, but [math]E_{ionization} \cong Z^2 \times 13.6 {\rm~eV}[/math] Link to comment Share on other sites More sharing options...
swansont Posted September 1, 2007 Share Posted September 1, 2007 Depends on how you use the term "decrease." The system energy is begative for a bound system (the zero is taken to be when the particles are far apart), so the energy becomes a larger negative number for the orbitals closer to the nucleus. The formula Ben gave works for a single-electron system. Link to comment Share on other sites More sharing options...
Meir Achuz Posted October 9, 2007 Share Posted October 9, 2007 Can you give me the energy expression for an electron?And also, does the energy of an electron decrease, or does the energy of the Energy shell decrease while moving nearer to the nucleus? It seems that you mean the energy of an electron bound to a nucleus. For that case, E=-Zme^4/2n^2 in Gaussian units. Since E~-1/n^2, the electron energy becomes more negative if it moves closer to the nucleus (lower n). The "energy of the energy shell" is just a formula used to calculate the electorn energy, so they are equal. Link to comment Share on other sites More sharing options...
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