mooeypoo Posted June 23, 2007 Share Posted June 23, 2007 Guys, I have some homework and the answer itself matters less - I just can't figure out *how* to do these type of questions.. I figure it has to do with an elaborate chain rule, but.. I can't do it right. I would appreciate help in this. btw, sorry if this is in the wrong forum - I couldn't find the goold ol' "Homework Help" forum. The question is this: f(x) = 2^[3^(x^2)] find dy/dx. Again, I *have* a final answer, I just don't understand how to do the chain rule itself on this one.. it seems like a double chain rule? ergh. Anyone has some sort of method/trick for these type of questions? Thanks! ~moo Link to comment Share on other sites More sharing options...
w=f[z] Posted June 23, 2007 Share Posted June 23, 2007 Do a series of substitutions. For example; let [math]f=2^t , \ t=3^{x^2}[/math] [math]\Rightarrow \frac{df}{dt}=2^t \ln{2}[/math] So [math]2^{3^{x^2}} \ln{2} [/math] will be in your answer. Then let [math]x^2=s[/math] and differentiate [math]3^s \Rightarrow 3^s\ln{3} \Rightarrow 3^{x^2} \ln{3} [/math], so that too will be in your answer via the chain rule and so on. See the pattern? Good luck chap, w=f[z] Link to comment Share on other sites More sharing options...
mooeypoo Posted June 23, 2007 Author Share Posted June 23, 2007 That sux. Thanks though.. hehe.. I'll have to REALLY practice on that one, the multiple chainrule thing is confusing. I see the point now.. but.. er. I need practice, I think. Thanks ~moo Link to comment Share on other sites More sharing options...
Country Boy Posted September 14, 2007 Share Posted September 14, 2007 That sux. Thanks though.. hehe.. I'll have to REALLY practice on that one, the multiple chainrule thing is confusing. I see the point now.. but.. er. I need practice, I think. Thanks ~moo So basically, then it is your ATTITUDE that is the problem rather than the chain rule. Link to comment Share on other sites More sharing options...
the tree Posted September 14, 2007 Share Posted September 14, 2007 So basically, then it is your ATTITUDE that is the problem rather than the chain rule.What precisely is wrong with Moo's attitude. Trying, asking for help and being aware of when he needs more practice seems a pretty good attitude to me. 1 Link to comment Share on other sites More sharing options...
mooeypoo Posted September 15, 2007 Author Share Posted September 15, 2007 What precisely is wrong with Moo's attitude. Trying, asking for help and being aware of when he needs more practice seems a pretty good attitude to me. "She." But yeah, I didn't think there was nothing wrong with my attitude, this is a request for help, not an life-or-death argument. I just figured if someone's that critical of those who ask for help, he doesn't deserve responses back. Plus, w=f[z] was so helpful, I didn't want to degrade the thread. Thanks to all that helped, I finished the course with an A-, which, considering the fact I am a full time employee, it's not too bad at all. Cheers, ~moo Link to comment Share on other sites More sharing options...
Country Boy Posted September 15, 2007 Share Posted September 15, 2007 "That sux" Link to comment Share on other sites More sharing options...
mooeypoo Posted September 15, 2007 Author Share Posted September 15, 2007 Yeah, humor... The rest of what I said showed that I meant it as a "oh my oh my how complicated, how annoying that I need to sit on my tushy and study". I'll try to avoid it next time. In any case, Really, we're taking things way out of proportion. I didn't mean it literally sux, and in case my assumption that you didn't mean to offend anyone is true, let's just drop the entire subject. Seriously. Let's practice math, instead, it's a lot more productive. ~moo Link to comment Share on other sites More sharing options...
Fuzzwood Posted September 15, 2007 Share Posted September 15, 2007 So in final you'll get [math] 2^{3^{x^2}} \ln{2} * 3^{x^2} \ln{3} * 2x [/math] right? I always sucked at these things, but i want to know if i can finally do it too Link to comment Share on other sites More sharing options...
joshua.cook Posted September 27, 2007 Share Posted September 27, 2007 f'=2(^3(^(x^2)))ln2*3(^(x^2))ln3*2x Link to comment Share on other sites More sharing options...
Phi for All Posted September 27, 2007 Share Posted September 27, 2007 What precisely is wrong with Moo's attitude. Trying, asking for help and being aware of when he needs more practice seems a pretty good attitude to me.I'm just going to be proactive here and praise the tree for his support. I want you to know how much the Staff appreciates positive feedback. It's too easy to go out of our ways to criticize. Thanks, the tree, you've earned yourself some reputation there. And mooeypoo, you just keep asking the questions darlin. It's great to have you here in the US away from all the tension. I hope your family is well. 1 Link to comment Share on other sites More sharing options...
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