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Simple Intregation


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I know that the intregation of [math]\frac{sinx}{cos^2x}[/math] is [math]secx[/math].


But I'm not sure how to get to the answer. I started off by using the trigonometric identity: [math]cos^2x + sin^2x = 1[/math].


Therefore, [math]\frac{sinx}{1-sin^2x}[/math]. Now what?

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