Jump to content

Can someone help me how to do this

Recommended Posts

HOw much heat is transferred when 8 g of Nitrogen(N2) reacts with 15 g of Hydrogen H2 according to the following equation

N2(g)+3H2--->2NH3(g) enthalpy change is 46.2kJ


I have no idea where to start this problem

Link to post
Share on other sites
  • 2 weeks later...

If you wanted to check your work:


You have 0.2855 mol (8 g/28.02 g) N2 and 7.44 mol (15 g / 2.016 g) H2. The limiting reagent is the N2 0.29 mol N2 will require 0.2855*3 mole of H2 = 0.8565 mol H2 while using 7.44 mol H2 will require 7.44/3 mol N2 = 2.48 mol N2; thus you dont have enough N2 to use all of the hydrogen (H2 is in excess)


Then using the equation eVon gave:


Enthalpy = (0.2855 mol)*(46.2 kJ / mol ) = 13.19 kJ for the reaction.





Have homework questions in chemistry, math or physics?

Who Likes Homework -- http://www.wholikeshomework.com

Link to post
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.